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Saturday, February 13, 2016

Java program to check armstrong number

This java program checks if a number is Armstrong or not. Armstrong number is a number which is equal to sum of digits raise to the power total number of digits in the number. Some Armstrong numbers are: 0, 1, 4, 5, 9, 153, 371, 407, 8208 etc.

Java programming code

import java.util.Scanner;
 
class ArmstrongNumber
{
public static void main(String args[])
{
int n, sum = 0, temp, remainder, digits = 0;
 
Scanner in = new Scanner(System.in);
System.out.println("Input a number to check if it is an Armstrong number");
n = in.nextInt();
 
temp = n;
 
// Count number of digits
 
while (temp != 0) {
digits++;
temp = temp/10;
}
 
temp = n;
 
while (temp != 0) {
remainder = temp%10;
sum = sum + power(remainder, digits);
temp = temp/10;
}
 
if (n == sum)
System.out.println(n + " is an Armstrong number.");
else
System.out.println(n + " is not an Armstrong number.");
}
 
static int power(int n, int r) {
int c, p = 1;
 
for (c = 1; c <= r; c++)
p = p*n;
 
return p;
}
}
Download Armstrong number program class file.
Output of program:
Armstrong number java program output
Using one more loop in the above code you can generate Armstrong numbers from 1 to n(say) or between two integers (a to b).

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