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Saturday, February 13, 2016

Java program to transpose matrix

This java program find transpose of a matrix of any order.

Java programming source code

import java.util.Scanner;
 
class TransposeAMatrix
{
public static void main(String args[])
{
int m, n, c, d;
 
Scanner in = new Scanner(System.in);
System.out.println("Enter the number of rows and columns of matrix");
m = in.nextInt();
n = in.nextInt();
 
int matrix[][] = new int[m][n];
 
System.out.println("Enter the elements of matrix");
 
for ( c = 0 ; c < m ; c++ )
for ( d = 0 ; d < n ; d++ )
matrix[c][d] = in.nextInt();
 
int transpose[][] = new int[n][m];
 
for ( c = 0 ; c < m ; c++ )
{
for ( d = 0 ; d < n ; d++ )
transpose[d][c] = matrix[c][d];
}
 
System.out.println("Transpose of entered matrix:-");
 
for ( c = 0 ; c < n ; c++ )
{
for ( d = 0 ; d < m ; d++ )
System.out.print(transpose[c][d]+"\t");
 
System.out.print("\n");
}
}
}
Download Transpose matrix program class file.
Output of program:
transpose matrix
This code can be used to check if a matrix symmetric or not, just compare the matrix with it's transpose if they are same then it's symmetric otherwise non symmetric, also it's useful for calculating orthogonality of a matrix.

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